schmittlauch/youtube-dl
1
0
Fork 0
Code Issues Pull requests Releases Wiki Activity

[YoutubeDL] Do not require default output template to be set

Browse source
This commit is contained in:
Philipp Hagemeister 2014-04-30 10:02:03 +02:00
parent b30b8698ea
commit acd69589a5
4 changed files with 12 additions and 6 deletions
Download patch file Download diff file Expand all files Collapse all files

9
youtube_dl/YoutubeDL.py
View file

@ -31,6 +31,7 @@ from .utils import (
ContentTooShortError,
date_from_str,
DateRange,
DEFAULT_OUTTMPL,
determine_ext,
DownloadError,
encodeFilename,
@ -440,7 +441,8 @@ class YoutubeDL(object):
if v is not None)
template_dict = collections.defaultdict(lambda: 'NA', template_dict)
tmpl = os.path.expanduser(self.params['outtmpl'])
outtmpl = self.params.get('outtmpl', DEFAULT_OUTTMPL)
tmpl = os.path.expanduser(outtmpl)
filename = tmpl % template_dict
return filename
except ValueError as err:
@ -1025,10 +1027,11 @@ class YoutubeDL(object):
def download(self, url_list):
"""Download a given list of URLs."""
outtmpl = self.params.get('outtmpl', DEFAULT_OUTTMPL)
if (len(url_list) > 1 and
'%' not in self.params['outtmpl']
'%' not in outtmpl
and self.params.get('max_downloads') != 1):
raise SameFileError(self.params['outtmpl'])
raise SameFileError(outtmpl)
for url in url_list:
try: